A student places an irregularly shaped mineral sample with a mass of 84\text{ g} into a gr… — Armed Services Vocational Aptitude Battery (ASVAB)

A student places an irregularly shaped mineral sample with a mass of $84\text{ g}$ into a graduated cylinder containing $40\text{ mL}$ of water. The water level rises to $68\text{ mL}$ . What is the density of the mineral in grams per cubic centimeter ( $\text{g/cm}^3$ )?

Answer: 3 g/cm^3

Answer

The density of the mineral is 3 g/cm³.

The volume of the mineral is found through liquid displacement:

68\text{ mL} - 40\text{ mL} = 28\text{ mL} = 28\text{ cm}^3

. Dividing the mass of the mineral (

84\text{ g}

) by its volume (

28\text{ cm}^3

) yields a density of

3\text{ g/cm}^3

Step-by-Step Solution

Determine the volume of the mineral using the water displacement method.

Volume = 68 mL - 40 mL = 28 mL = 28 cm³

When a solid is completely submerged, the volume of liquid displaced is equal to the volume of the solid.

Calculate the density of the mineral using the formula Density = Mass / Volume.

Density = 84 g / 28 cm³ = 3 g/cm³

Density is a characteristic physical property defined as the amount of mass per unit volume of a substance.

Key Concept

Density and Volume Determination via Water Displacement

Estimated Time:45s

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