Question

Difficulty: EasyElectrical Power and Watt's Law

A direct-current (DC) ventilation blower operates on a 28 V28\text{ V} aircraft electrical bus and draws a steady current of 5 A5\text{ A}. How many watts (W\text{W}) of electrical power are consumed by the blower?

Answer: 140 W

Answer

The power consumed by the blower is 140 W140\text{ W}.
According to Watt's Law, electrical power (PP) dissipated by a direct-current device equals the product of the applied voltage (VV) and the current (II). Multiplying 28 V28\text{ V} by 5 A5\text{ A} gives 140 W140\text{ W}.

Step-by-Step Solution

1
Identify the known electrical quantities given in the scenario.
Voltage V=28 VV = 28\text{ V} and Current I=5 AI = 5\text{ A}.
Identifying the known parameters determines which form of Watt's Law to use.
2
Apply the fundamental Watt's Law formula for electrical power (P=V×IP = V \times I).
P=28 V×5 A=140 WP = 28\text{ V} \times 5\text{ A} = 140\text{ W}.
Electrical power in a direct-current circuit is calculated by multiplying the potential difference across the load by the current flowing through it.

Key Concept

Watt's Law for DC Power (P=V×IP = V \times I)
Estimated Time:45s
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