Question

Difficulty: MediumSolving One-Variable Inequalities

A student needs to solve the following algebraic inequality:

7−2(x−3)≥4x−57 - 2(x - 3) \geq 4x - 5

What is the correct solution for xx?

  1. A
    x≥3x \geq 3
  2. B
    x≥10x \geq 10
  3. x≤3x \leq 3Answer
  4. D
    x≤−3x \leq -3

Answer

The correct solution is x≤3x \leq 3.
The correct answer is derived by carefully distributing the −2-2, combining the constants, grouping the variables on one side, and dividing by −6-6. Crucially, dividing by a negative coefficient triggers the rule to flip the ≥\geq sign to ≤\leq, resulting in x≤3x \leq 3.

Step-by-Step Solution

1
Distribute the −2-2 into the parentheses on the left side of the inequality.
7−2x+6≥4x−57 - 2x + 6 \geq 4x - 5
To eliminate the parentheses and allow like terms to be combined.
2
Combine the constant terms on the left side.
13−2x≥4x−513 - 2x \geq 4x - 5
Adding 77 and 66 simplifies the left side of the algebraic expression.
3
Subtract 4x4x from both sides of the inequality.
13−6x≥−513 - 6x \geq -5
To group all terms containing the variable xx onto the left side.
4
Subtract 1313 from both sides.
−6x≥−18-6x \geq -18
To isolate the variable term on one side and the constant values on the other.
5
Divide both sides by −6-6 and reverse the inequality symbol.
x≤3x \leq 3
Whenever an inequality is multiplied or divided by a negative number, the direction of the inequality sign must be flipped.

Key Concept

Solving multi-step inequalities, including the distributive property and the inequality flip rule for negative coefficients.
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