Question

Difficulty: EasyMechanics and Motion

A 15 kg15\text{ kg} sled slides across a smooth ice rink at a constant velocity of 4 m/s4\text{ m/s}. What is the magnitude of the sled's momentum in kilogram-meters per second (kg⋅m/s\text{kg}\cdot\text{m/s})?

Answer: 60 kg·m/s

Answer

60 kg·m/s
Linear momentum is calculated using the formula p=m×vp = m \times v. For an object with a mass of 15 kg15\text{ kg} moving at 4 m/s4\text{ m/s}, the momentum is 15 kg×4 m/s=60 kg⋅m/s15\text{ kg} \times 4\text{ m/s} = 60\text{ kg}\cdot\text{m/s}.

Step-by-Step Solution

1
Identify the given mass and velocity values.
m=15 kgm = 15\text{ kg} and v=4 m/sv = 4\text{ m/s}
Linear momentum depends directly on an object's mass and its velocity.
2
Apply the momentum formula p=m×vp = m \times v.
p=15 kg×4 m/s=60 kg⋅m/sp = 15\text{ kg} \times 4\text{ m/s} = 60\text{ kg}\cdot\text{m/s}
Multiplying mass by velocity calculates the magnitude of linear momentum.

Key Concept

Linear momentum is the product of an object's mass and its velocity (p=mvp = mv).
Estimated Time:45s
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