Question

Difficulty: MediumScale Drawings

A structural engineer is analyzing a blueprint for a steel bridge truss. The blueprint uses a scale where 78 inch\frac{7}{8}\text{ inch} represents an actual length of 21 feet21\text{ feet}. If a particular support beam measures 6.5 inches6.5\text{ inches} on the blueprint, what is the actual length of this beam in feet?

Answer: 156 feet

Answer

156
The correct answer is found by establishing a proportion based on the scale. Since 78 inch\frac{7}{8}\text{ inch} equals 21 feet21\text{ feet}, 1 inch1\text{ inch} must equal 21÷7821 \div \frac{7}{8}, which is 24 feet24\text{ feet}. Multiplying the blueprint length of 6.5 inches6.5\text{ inches} by this unit rate of 2424 gives an actual length of 156 feet156\text{ feet}.

Step-by-Step Solution

1
Determine the unit scale factor in feet per inch.
21÷78=24 feet/inch21 \div \frac{7}{8} = 24\text{ feet/inch}
Finding the actual distance represented by a single inch creates a simple multiplier for any dimension on the blueprint.
2
Multiply the measurement on the blueprint by the unit scale factor.
6.5×24=156 feet6.5 \times 24 = 156\text{ feet}
Scaling up the drawing measurement by the unit rate yields the actual real-world length of the beam.

Key Concept

Direct proportions and unit rates in scale drawings

Alternative Method

You can set up a direct proportion: 7821=6.5x\frac{\frac{7}{8}}{21} = \frac{6.5}{x}. Cross-multiplying gives 78x=136.5\frac{7}{8}x = 136.5. Multiplying both sides by 87\frac{8}{7} yields x=156x = 156.
Estimated Time:1m 0s
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