A portable work light operates on a simple direct-current circuit. When switched on, an el… — Armed Services Vocational Aptitude Battery (ASVAB)

A portable work light operates on a simple direct-current circuit. When switched on, an electric current of $2\text{ A}$ passes through the bulb, which has a resistance of $3\,\Omega$ . According to Ohm's law ( $V = I \times R$ ), what is the voltage supplied by the battery?

A
$1.5\text{ V}$
B
$5\text{ V}$
$6\text{ V}$ Answer
D
$0.67\text{ V}$

Answer

The voltage supplied by the battery is

6\text{ V}

According to Ohm's law, voltage (

V

) equals current (

I

) multiplied by resistance (

R

). Multiplying

2\text{ A}

3\,\Omega

gives

6\text{ V}

Step-by-Step Solution

Identify the given electrical quantities from the problem.

Current

I = 2\text{ A}

and resistance

R = 3\,\Omega

Ohm's law requires current and resistance to determine voltage.

Apply Ohm's law formula

V = I \times R

V = 2\text{ A} \times 3\,\Omega = 6\text{ V}

Multiplying electric current by internal resistance calculates the total potential difference (voltage).

Key Concept

Ohm's law states that the electrical potential difference (voltage) across a conductor is directly proportional to the current flowing through it, given by

V = I \times R

Estimated Time:40s

Question

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Topics

More questions from this topic