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Difficulty: MediumUS Customary Capacity and Volume

An industrial pump requires 22 gallons, 33 quarts, and 11 pint of lubricating oil to completely fill its reservoir. If a maintenance technician needs to completely fill the empty reservoirs of 88 identical pumps, what is the total volume of oil required, in gallons?

  1. A
    21
  2. 23Answer
  3. C
    46
  4. D
    92

Answer

The total volume of oil required is 23 gallons.
To find the total, you must first convert the requirement for one pump into a standard unit: 22 gallons is 88 quarts, plus 33 quarts, plus 11 pint (0.50.5 quarts) equals 11.511.5 quarts per pump. Multiplying 11.511.5 quarts by 88 pumps yields 9292 quarts. Since there are 44 quarts in a gallon, dividing 9292 by 44 gives the correct total of 2323 gallons.

Step-by-Step Solution

1
Convert the capacity of one pump into a single unit, such as quarts.
22 gallons = 88 quarts, and 11 pint = 0.50.5 quarts. Adding these together gives 8+3+0.5=11.58 + 3 + 0.5 = 11.5 quarts per pump.
Standardizing all measurements into one unit prevents addition errors and simplifies the multiplication step.
2
Multiply the single-pump volume by the total number of pumps.
11.511.5 quarts ×8\times 8 pumps = 9292 quarts.
This determines the total volume of oil needed for all the equipment combined.
3
Convert the total volume back into gallons.
92÷4=2392 \div 4 = 23 gallons.
The question specifically asks for the final answer in gallons, and there are 44 quarts in 11 gallon.

Key Concept

Multiplying mixed US Customary capacity measurements and converting between units.
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Topics

US Customary Capacity and Volume

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