Question

Difficulty: HardStars, Galaxies, and the Universe

A team of astrophysicists detects the spectral signature of a supernova in a spiral galaxy located 2.5×1062.5 \times 10^6 light-years from Earth. Which statement correctly interprets the physical meaning of this measurement in the context of astronomical observations?

  1. The light captured by Earth's telescopes today was emitted 2.5×1062.5 \times 10^6 years ago because a light-year is a unit of distance representing how far light travels in one Earth year.Answer
  2. B
    The explosive phase of the supernova lasted for a total duration of 2.5×1062.5 \times 10^6 years because light-years measure elapsed cosmic time.
  3. C
    The emitted photons traveled across interstellar space at a speed of 2.5×106 km/s2.5 \times 10^6\text{ km/s} before striking Earth's sensors.
  4. D
    The supernova is located 2.5×1062.5 \times 10^6 astronomical units away, which is based on the average distance between Earth and the Sun.

Answer

The light captured by Earth's telescopes today was emitted 2.5×1062.5 \times 10^6 years ago because a light-year is a unit of distance representing how far light travels in one Earth year.
A light-year is defined as the distance that light travels in a vacuum in one Julian year. Because light travels at a constant finite speed (cc), when astronomers observe an object located 2.5×1062.5 \times 10^6 light-years away, they are viewing photons that departed the source 2.5×1062.5 \times 10^6 years ago. Thus, looking across vast cosmic distances is equivalent to observing the universe's past.

Step-by-Step Solution

1
Define the astronomical unit 'light-year'
A light-year is strictly a unit of length/distance, defined as the distance an electromagnetic wave travels in a vacuum over the course of one Julian year (9.46×1012 km9.46 \times 10^{12}\text{ km}).
Clarifies the fundamental physical quantity being measured.
2
Relate distance, speed of light, and lookback time
Since light travels at constant speed cc, covering a distance of 2.5×1062.5 \times 10^6 light-years requires exactly 2.5×1062.5 \times 10^6 years of travel time.
Establishes that looking deeper into space corresponds to observing events further in the cosmic past.
3
Evaluate observational implications
The observation on Earth reflects the physical state of the galaxy and star as it existed 2.5×1062.5 \times 10^6 years ago.
Connects astronomical distance measurement with lookback time.

Key Concept

Astronomical distance units and lookback time
Estimated Time:1m 15s
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