An automated cargo tug applies a forward thrust of 24,000 \text{ N} to a 1,000 \text{ kg} … — Armed Services Vocational Aptitude Battery (ASVAB)

An automated cargo tug applies a forward thrust of $24,000 \text{ N}$ to a $1,000 \text{ kg}$ supply sled. If the ground surface creates a constant opposing frictional force of $4,000 \text{ N}$ , what is the resulting acceleration of the sled?

$20 \text{ m/s}^2$ Answer
B
$24 \text{ m/s}^2$
C
$2 \text{ m/s}^2$
D
$0.05 \text{ m/s}^2$

Answer

20 \text{ m/s}^2

The sled experiences a forward thrust of

24,000 \text{ N}

and a backward frictional force of

4,000 \text{ N}

, resulting in a net force of

20,000 \text{ N}

. Using Newton's Second Law (

F = ma

), dividing the net force (

20,000 \text{ N}

) by the mass (

1,000 \text{ kg}

) gives an acceleration of

20 \text{ m/s}^2

Step-by-Step Solution

Calculate the net force acting on the sled.

F_{\text{net}} = 24,000 \text{ N} - 4,000 \text{ N} = 20,000 \text{ N}

Acceleration is determined by the net force, which is the applied force minus any opposing forces like friction.

Apply Newton's Second Law (

F = ma

) to find the acceleration.

a = \frac{F_{\text{net}}}{m} = \frac{20,000 \text{ N}}{1,000 \text{ kg}} = 20 \text{ m/s}^2

Rearranging the formula to solve for acceleration gives

a = \frac{F}{m}

Key Concept

Newton's Second Law (

F = ma

)

Estimated Time:45s

Question

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Topics

More questions from this topic