Question

Difficulty: EasyFraction Operations

A runner completes 25\frac{2}{5} of a mile as a warm-up and then runs another 13\frac{1}{3} of a mile. What is the total distance, in miles, the runner covered?

  1. 1115\frac{11}{15}Answer
  2. B
    38\frac{3}{8}
  3. C
    215\frac{2}{15}
  4. D
    15\frac{1}{5}

Answer

1115\frac{11}{15}
To find the total distance, the fractions must be added. Since they have unlike denominators (5 and 3), the lowest common denominator (15) must be found. Converting the fractions yields 615\frac{6}{15} and 515\frac{5}{15}. Adding the numerators provides the final total of 1115\frac{11}{15}.

Step-by-Step Solution

1
Identify the operation needed.
Addition: 25+13\frac{2}{5} + \frac{1}{3}
The question asks for the total distance covered, requiring the sum of the two distinct parts of the run.
2
Find a common denominator for 5 and 3.
The lowest common multiple of 5 and 3 is 15.
Fractions must have a common denominator before they can be added together.
3
Convert both fractions to have a denominator of 15.
25=615\frac{2}{5} = \frac{6}{15} and 13=515\frac{1}{3} = \frac{5}{15}
To maintain the same value, multiply the numerator and denominator of the first fraction by 3, and the second fraction by 5.
4
Add the numerators and keep the common denominator.
615+515=1115\frac{6}{15} + \frac{5}{15} = \frac{11}{15}
Once denominators are the same, only the numerators are added to find the total.

Key Concept

Adding Fractions with Unlike Denominators
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