Question

Difficulty: Very hardUS Customary Weight Measurements

A logistics officer must load four distinct cargo items onto a transport aircraft. To maintain proper weight distribution, the items must be loaded in a specific sequence based on their total weight. Arrange the following cargo items in order from lightest to heaviest.

  1. 1A crate weighing 98\frac{9}{8} tons
  2. 2A pallet weighing 36,48036,480 ounces
  3. 3A container weighing 1.151.15 tons
  4. 4A supply pod weighing 11 ton and 5,2805,280 ounces

Answer

The correct order from lightest to heaviest is: the crate (2,2502,250 lbs), the pallet (2,2802,280 lbs), the container (2,3002,300 lbs), and the supply pod (2,3302,330 lbs).
By converting all items to a common unit (pounds), we can accurately compare their weights: the crate is 2,2502,250 lbs, the pallet is 2,2802,280 lbs, the container is 2,3002,300 lbs, and the supply pod is 2,3302,330 lbs. Arranging these from lightest to heaviest yields the correct sequence.

Step-by-Step Solution

1
Convert the weight of the crate to pounds.
2,2502,250 lbs
Standardizing all weights to a single unit (pounds) allows for direct comparison. 98×2,000=2,250\frac{9}{8} \times 2,000 = 2,250.
2
Convert the weight of the pallet to pounds.
2,2802,280 lbs
Since there are 1616 ounces in a pound, divide by 1616. 36,480÷16=2,28036,480 \div 16 = 2,280.
3
Convert the weight of the container to pounds.
2,3002,300 lbs
Since there are 2,0002,000 pounds in a ton, multiply by 2,0002,000. 1.15×2,000=2,3001.15 \times 2,000 = 2,300.
4
Convert the weight of the supply pod to pounds.
2,3302,330 lbs
The pod has mixed units. Convert the ton to 2,0002,000 pounds and the ounces to pounds (5,280÷16=3305,280 \div 16 = 330). Adding them gives 2,000+330=2,3302,000 + 330 = 2,330.
5
Arrange the converted weights in ascending order.
2,250<2,280<2,300<2,3302,250 < 2,280 < 2,300 < 2,330
The question asks for the items to be ordered from lightest to heaviest.

Key Concept

Multi-step conversion between ounces, pounds, and tons.
Estimated Time:3m 0s
Rate this question