Question

Difficulty: MediumEvaluating Algebraic Expressions

Given the values x=12x = \frac{1}{2}, y=−4y = -4, and z=−2z = -2, determine the value of the expression 4x2y−yz34x^2y - yz^3.

Answer: -36

Answer

-36
The correct answer is derived by substituting the variables accurately, applying the exponents (especially noting that a negative base to an odd power remains negative), and strictly following the order of operations to multiply and then subtract.

Step-by-Step Solution

1
Substitute x=12x = \frac{1}{2}, y=−4y = -4, and z=−2z = -2 into the expression.
4(12)2(−4)−(−4)(−2)34(\frac{1}{2})^2(-4) - (-4)(-2)^3
Variable substitution must be done exactly as given to prepare for evaluation.
2
Evaluate the terms with exponents.
(12)2=14(\frac{1}{2})^2 = \frac{1}{4} and (−2)3=−8(-2)^3 = -8. The expression becomes 4(14)(−4)−(−4)(−8)4(\frac{1}{4})(-4) - (-4)(-8).
According to the order of operations (PEMDAS), exponents must be resolved before multiplication.
3
Perform the multiplication operations from left to right.
4(14)(−4)=1(−4)=−44(\frac{1}{4})(-4) = 1(-4) = -4 and (−4)(−8)=32(-4)(-8) = 32. The expression is now −4−32-4 - 32.
Multiplication is the next step in the order of operations. Note that multiplying two negative numbers results in a positive product.
4
Perform the final subtraction.
−4−32=−36-4 - 32 = -36
Subtracting a positive number from a negative number moves further left on the number line.

Key Concept

Evaluating algebraic expressions using rational numbers, negative bases, and the correct order of operations.
Estimated Time:1m 0s
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