Question

Difficulty: MediumVoltage and Electromotive Force (EMF)

An industrial controller module requires a total electromotive force (EMF) of 0.12 kV0.12\text{ kV} for its backup power rail. If standard 1.5 V1.5\text{ V} alkaline cells are connected in series-aiding to supply the rail, how many cells are required?

Answer: 80 cells

Answer

80 cells
The total requirement is 0.12 kV0.12\text{ kV}, which equals 120 V120\text{ V}. Since series-aiding cells add their electromotive forces directly, dividing the total required voltage of 120 V120\text{ V} by 1.5 V1.5\text{ V} per cell gives exactly 8080 cells.

Step-by-Step Solution

1
Convert the required electromotive force from kilovolts (kV) to standard volts (V)
0.12 kV×1000=120 V0.12\text{ kV} \times 1000 = 120\text{ V}
The prefix kilo- denotes a multiplier of 10001000, so the potential difference must be converted to base units to match individual cell ratings.
2
Calculate the number of series cells needed by dividing total EMF by the EMF of a single cell
n=120 V1.5 V/cell=80 cellsn = \frac{120\text{ V}}{1.5\text{ V/cell}} = 80\text{ cells}
When electrical cells are connected in series-aiding configuration, their individual voltages add directly (Vtotal=n×VcellV_{\text{total}} = n \times V_{\text{cell}}).

Key Concept

Series electromotive force summation and metric prefix voltage conversion
Estimated Time:1m 0s
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