A technician connects a 10\text{ }\mu\text{F} capacitor in parallel with a 22\text{ }\mu\t… — Armed Services Vocational Aptitude Battery (ASVAB)

A technician connects a $10\text{ }\mu\text{F}$ capacitor in parallel with a $22\text{ }\mu\text{F}$ capacitor in a power supply filter circuit. What is the total equivalent capacitance of this combination in microfarads ( $\mu\text{F}$ )?

Answer: 32 uF

Answer

32 uF

When capacitors are connected in parallel, their total capacitance is the direct sum of the individual capacitances:

C_{\text{total}} = C_1 + C_2

. Adding

10\text{ }\mu\text{F}

and

22\text{ }\mu\text{F}

results in a total equivalent capacitance of

32\text{ }\mu\text{F}

Step-by-Step Solution

Identify the circuit configuration and the relevant formula for equivalent capacitance.

The two capacitors are connected in parallel, meaning their total capacitance is the sum of their individual capacitances:

C_{\text{total}} = C_1 + C_2

Connecting capacitors in parallel effectively increases the total plate surface area, allowing more electric charge to be stored at a given voltage.

Calculate the sum of the individual capacitances.

C_{\text{total}} = 10\text{ }\mu\text{F} + 22\text{ }\mu\text{F} = 32\text{ }\mu\text{F}

Direct addition yields the total equivalent capacitance.

Key Concept

Total capacitance in a parallel circuit is calculated by directly adding the individual capacitances (

C_{\text{total}} = C_1 + C_2 + \dots

Estimated Time:45s

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