Question

Difficulty: EasyParallel Circuits

Four identical 40 Ω40\ \Omega heating elements are connected in parallel across a 120 V120\text{ V} power line. What is the total equivalent resistance of this circuit?

  1. A
    160 Ω160\ \Omega
  2. 10 Ω10\ \OmegaAnswer
  3. C
    40 Ω40\ \Omega
  4. D
    20 Ω20\ \Omega

Answer

The total equivalent resistance of the circuit is 10 Ω10\ \Omega.
For NN identical resistors of equal resistance RR connected in parallel, the total equivalent resistance is simply the resistance of one branch divided by the total number of branches: Req=RN=40 Ω4=10 ΩR_{\text{eq}} = \frac{R}{N} = \frac{40\ \Omega}{4} = 10\ \Omega.

Step-by-Step Solution

1
Identify the number of parallel branches (NN) and individual branch resistance (RR).
N=4N = 4 identical branches, each with R=40 ΩR = 40\ \Omega.
Recognizing identical parallel branches allows the use of the equal-resistor shortcut formula.
2
Apply the parallel equivalent resistance formula for identical resistors: Req=RNR_{\text{eq}} = \frac{R}{N}.
Req=40 Ω4=10 ΩR_{\text{eq}} = \frac{40\ \Omega}{4} = 10\ \Omega.
Connecting resistors in parallel creates multiple paths for electron flow, reducing the total circuit resistance below that of any individual branch.

Key Concept

Total Equivalent Resistance of Equal Parallel Resistors
Estimated Time:45s
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