Question

Difficulty: Very hardAverage Speed

A military cargo aircraft flies from Base Alpha to Base Bravo at an average speed of 300300 miles per hour. Upon arrival, the aircraft spends exactly 11 hour and 3030 minutes on the ground being loaded. It then returns to Base Alpha along the exact same route at an average speed of 600600 miles per hour. If the total elapsed time for the entire mission, from the initial departure to the final return, was 77 hours and 3030 minutes, what was the aircraft's overall average speed, in miles per hour, for the entire mission?

Answer: 320 mph

Answer

The aircraft's overall average speed for the entire mission was 320320 miles per hour.
The correct overall average speed is found by first calculating the total distance traveled, and then dividing it by the total elapsed time for the mission. By subtracting the 1.51.5-hour ground delay from the 7.57.5-hour total time, we find the aircraft flew for a total of 66 hours. Using the relationship D300+D600=6\frac{D}{300} + \frac{D}{600} = 6, we find the one-way distance DD is 12001200 miles. Therefore, the total round-trip distance is 24002400 miles. Dividing the 24002400 miles by the total mission time of 7.57.5 hours yields an overall average speed of 320320 mph.

Step-by-Step Solution

1
Determine the actual time the aircraft spent flying.
77 hours and 3030 minutes total minus 11 hour and 3030 minutes on the ground equals 66 hours of flight time.
The total elapsed time includes the ground time, which must be subtracted to isolate the time spent traveling at the given speeds.
2
Set up an equation to find the one-way distance between the bases.
Let DD be the one-way distance. D300+D600=6\frac{D}{300} + \frac{D}{600} = 6
Time equals distance divided by rate. The sum of the time for the outbound flight and the return flight equals the total flight time.
3
Solve the equation for the one-way distance (DD).
D=1200D = 1200 miles
2D600+D600=6⇒3D600=6⇒D200=6⇒D=1200\frac{2D}{600} + \frac{D}{600} = 6 \Rightarrow \frac{3D}{600} = 6 \Rightarrow \frac{D}{200} = 6 \Rightarrow D = 1200.
4
Calculate the total distance traveled during the entire mission.
1200×2=24001200 \times 2 = 2400 miles
The mission is a round trip, so the one-way distance must be doubled.
5
Calculate the overall average speed for the entire mission.
2400÷7.5=3202400 \div 7.5 = 320 miles per hour.
Overall average speed equals total distance divided by total elapsed time (which includes the ground delay).

Key Concept

Overall average speed is the total distance traveled divided by the total elapsed time, which includes any stationary delays. It cannot be calculated by simply averaging the individual speeds.

Alternative Method

Instead of solving for distance first, you can use the harmonic mean of the speeds to find the average speed while in the air: 2×300×600300+600=400 mph\frac{2 \times 300 \times 600}{300 + 600} = 400 \text{ mph}. The aircraft flew for 66 hours at an average of 400 mph400 \text{ mph}, covering 24002400 miles. Then, divide 24002400 miles by the total mission time (7.57.5 hours) to find the overall average speed: 320 mph320 \text{ mph}.
Estimated Time:3m 0s
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