Question

Difficulty: MediumSolving One-Variable Linear Equations

Determine the value of the variable yy that satisfies the given linear equation.

Answer:Given the equation 5(y−2)+3y=4y+26 5(y - 2) + 3y = 4y + 26 , the value of yy is 【9】.

Answer

9
By distributing the 55 to obtain 5y−105y - 10, combining the yy terms on the left to get 8y8y, and subsequently isolating yy through basic inverse operations (8y−4y=26+108y - 4y = 26 + 10), we determine that 4y=364y = 36, making y=9y = 9.

Step-by-Step Solution

1
Distribute the 5 to the terms inside the parentheses.
5y−10+3y=4y+265y - 10 + 3y = 4y + 26
Applying the distributive property removes the parentheses, allowing like terms to be combined.
2
Combine the like terms on the left side of the equation.
8y−10=4y+268y - 10 = 4y + 26
Simplifying each side individually makes it easier to isolate the variable.
3
Subtract 4y4y from both sides of the equation.
4y−10=264y - 10 = 26
This groups all terms containing the variable yy on one side of the equation.
4
Add 10 to both sides of the equation.
4y=364y = 36
This isolates the variable term by removing the constant from the left side.
5
Divide both sides by 4.
y=9y = 9
Dividing by the coefficient of yy yields the final value.

Key Concept

Solving linear equations with variables on both sides using the distributive property
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