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Question

Difficulty: EasyCalculating Distance

A naval submarine travels at a steady surface speed of 15 knots15\text{ knots} (nautical miles per hour) for 2 hours and 20 minutes2\text{ hours and } 20\text{ minutes} before submerging. What is the total distance traveled during this time?

  1. 35 nautical miles35\text{ nautical miles}Answer
  2. B
    33 nautical miles33\text{ nautical miles}
  3. C
    30 nautical miles30\text{ nautical miles}
  4. D
    350 nautical miles350\text{ nautical miles}

Answer

35 nautical miles35\text{ nautical miles}
The correct answer is found by converting the travel time of 2 hours and 20 minutes2\text{ hours and } 20\text{ minutes} into 213 hours2\frac{1}{3}\text{ hours}, and then multiplying this time by the speed of 15 knots15\text{ knots}. The calculation is 15×73=35 nautical miles15 \times \frac{7}{3} = 35\text{ nautical miles}.

Step-by-Step Solution

1
Convert the travel time into hours.
2 hours and 20 minutes=22060 hours=213 hours2\text{ hours and } 20\text{ minutes} = 2\frac{20}{60}\text{ hours} = 2\frac{1}{3}\text{ hours}.
Speed is given in knots (nautical miles per hour), so time must be uniformly converted to hours to compute distance accurately.
2
Multiply the speed by the time to find the total distance.
Distance=15×213=15×73=35 nautical miles\text{Distance} = 15 \times 2\frac{1}{3} = 15 \times \frac{7}{3} = 35\text{ nautical miles}.
The formula for distance is Distance=Rate×Time\text{Distance} = \text{Rate} \times \text{Time}.

Key Concept

Calculating distance by converting minutes into a fraction of an hour and multiplying by the rate of speed.
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Topics

Calculating Distance

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