Question

Difficulty: MediumWrenches

An apprentice mechanic is organizing a set of small fractional SAE ignition wrenches on a shop organizer rack. Arrange the following wrench opening sizes in order from smallest to largest opening width:

  1. 11/4 in1/4\text{ in}
  2. 29/32 in9/32\text{ in}
  3. 35/16 in5/16\text{ in}
  4. 411/32 in11/32\text{ in}
  5. 53/8 in3/8\text{ in}

Answer

The correct order from smallest to largest wrench opening is 1/4 in1/4\text{ in}, 9/32 in9/32\text{ in}, 5/16 in5/16\text{ in}, 11/32 in11/32\text{ in}, and 3/8 in3/8\text{ in}.
To arrange fractional SAE wrenches from smallest to largest, express each dimension with a common denominator of 3232: 1/4 in=8/32 in1/4\text{ in} = 8/32\text{ in}, 9/32 in=9/32 in9/32\text{ in} = 9/32\text{ in}, 5/16 in=10/32 in5/16\text{ in} = 10/32\text{ in}, 11/32 in=11/32 in11/32\text{ in} = 11/32\text{ in}, and 3/8 in=12/32 in3/8\text{ in} = 12/32\text{ in}. Comparing the numerators confirms that 8<9<10<11<128 < 9 < 10 < 11 < 12, establishing the ascending sequence: 1/4 in1/4\text{ in}, 9/32 in9/32\text{ in}, 5/16 in5/16\text{ in}, 11/32 in11/32\text{ in}, and 3/8 in3/8\text{ in}.

Step-by-Step Solution

1
Find the least common denominator for all given fractional wrench sizes (44, 3232, 1616, and 88).
The common denominator is 3232.
Converting all fractions to a common denominator allows for a direct comparison of their numerators.
2
Convert each fraction into equivalent thirty-seconds of an inch.
1/4 in=8/32 in1/4\text{ in} = 8/32\text{ in}, 9/32 in=9/32 in9/32\text{ in} = 9/32\text{ in}, 5/16 in=10/32 in5/16\text{ in} = 10/32\text{ in}, 11/32 in=11/32 in11/32\text{ in} = 11/32\text{ in}, and 3/8 in=12/32 in3/8\text{ in} = 12/32\text{ in}.
Multiplying both numerator and denominator by the appropriate factor preserves fractional value while standardizing units.
3
Arrange the values in ascending order by comparing their numerators.
8/32 in<9/32 in<10/32 in<11/32 in<12/32 in8/32\text{ in} < 9/32\text{ in} < 10/32\text{ in} < 11/32\text{ in} < 12/32\text{ in}, which corresponds to 1/4 in<9/32 in<5/16 in<11/32 in<3/8 in1/4\text{ in} < 9/32\text{ in} < 5/16\text{ in} < 11/32\text{ in} < 3/8\text{ in}.
Comparing numerators across equal denominators establishes the exact physical progression of tool opening sizes.

Key Concept

Fractional SAE wrench sizing and common denominator conversion
Estimated Time:1m 0s
Rate this question

Topics