Question

Difficulty: Very hardSolving Systems of Linear Equations

If 3x+5y=113x + 5y = 11 and 4x+9y=34x + 9y = 3, what is the value of the expression x+2yx + 2y?

  1. A
    22
  2. B
    4
  3. 2Answer
  4. D
    -2

Answer

2
The correct answer is 2. To solve the system, use the elimination method by multiplying the equations to create opposite or matching coefficients. Multiplying the first equation by 4 yields 12x+20y=4412x + 20y = 44. Multiplying the second equation by 3 yields 12x+27y=912x + 27y = 9. Subtracting the first equation from the second gives 7y=−357y = -35, so y=−5y = -5. Substituting y=−5y = -5 into the first original equation gives 3x−25=113x - 25 = 11, which simplifies to 3x=363x = 36, or x=12x = 12. Finally, substituting these values into the expression x+2yx + 2y gives 12+2(−5)=12−10=212 + 2(-5) = 12 - 10 = 2.

Step-by-Step Solution

1
Multiply the first equation by 4 and the second equation by 3 to prepare for elimination.
12x+20y=4412x + 20y = 44 and 12x+27y=912x + 27y = 9
Creating matching coefficients for xx allows us to eliminate it by subtracting the equations.
2
Subtract the first new equation from the second new equation.
(12x+27y)−(12x+20y)=9−44⇒7y=−35(12x + 27y) - (12x + 20y) = 9 - 44 \Rightarrow 7y = -35
This eliminates xx and leaves a simple equation with only yy.
3
Divide by 7 to solve for yy.
y=−5y = -5
Isolating yy gives its numerical value.
4
Substitute y=−5y = -5 back into the original first equation (3x+5y=113x + 5y = 11) and solve for xx.
3x+5(−5)=11⇒3x−25=11⇒3x=36⇒x=123x + 5(-5) = 11 \Rightarrow 3x - 25 = 11 \Rightarrow 3x = 36 \Rightarrow x = 12
This finds the corresponding value for xx.
5
Substitute x=12x = 12 and y=−5y = -5 into the requested expression x+2yx + 2y.
12+2(−5)=12−10=212 + 2(-5) = 12 - 10 = 2
The question asks for the value of this specific expression, not just the ordered pair.

Key Concept

Solving systems of linear equations using the elimination method and evaluating algebraic expressions.
Estimated Time:2m 0s
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