Question

Difficulty: MediumLevers and Fulcrums

A carpenter uses a claw hammer to extract a stubborn nail from a wooden board. The hammer acts as a first-class lever. The distance from the nail to the pivot point (fulcrum) on the hammer's head is 2 inches2\text{ inches}. The carpenter applies an effort force perpendicular to the handle at a distance of 16 inches16\text{ inches} from the pivot point. If a resistance force of 280 pounds280\text{ pounds} is required to extract the nail, how many pounds of effort force must the carpenter apply?

Answer: 35 pounds

Answer

35 pounds
In a first-class lever, the mechanical advantage is determined by the ratio of the effort arm to the resistance arm. The hammer provides a mechanical advantage of 16/2=816 / 2 = 8. Therefore, the effort force required is the load divided by 8, which is 280/8=35 pounds280 / 8 = 35\text{ pounds}. Using the fundamental torque balance equation (F1×d1=F2×d2F_1 \times d_1 = F_2 \times d_2), 280×2=560280 \times 2 = 560, and 560/16=35560 / 16 = 35.

Step-by-Step Solution

1
State the torque balance equation for a lever.
FE×dE=FR×dRF_E \times d_E = F_R \times d_R
For the lever to overcome the resistance, the torque applied by the effort must equal the torque exerted by the load.
2
Substitute the given values into the equation.
FE×16=280×2F_E \times 16 = 280 \times 2
The effort distance (dEd_E) is 16 inches16\text{ inches}, the resistance force (FRF_R) is 280 pounds280\text{ pounds}, and the resistance distance (dRd_R) is 2 inches2\text{ inches}.
3
Calculate the total torque of the resistance.
280×2=560 inch-pounds280 \times 2 = 560\text{ inch-pounds}
This represents the total rotational force required to loosen the nail.
4
Solve for the effort force (FEF_E).
FE=560/16=35 poundsF_E = 560 / 16 = 35\text{ pounds}
Dividing the total required torque by the longer effort arm gives the smaller effort force needed.

Key Concept

Torque Balance and Mechanical Advantage
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