A handheld emergency flashlight is powered by four 1.5\text{ V} alkaline cells connected i… — Armed Services Vocational Aptitude Battery (ASVAB)

A handheld emergency flashlight is powered by four $1.5\text{ V}$ alkaline cells connected in series aiding. What is the total electromotive force (EMF) supplied to the flashlight bulb?

A
$1.5\text{ V}$
$6.0\text{ V}$ Answer
C
$6.0\text{ A}$
D
$0.375\text{ V}$

Answer

6.0\text{ V}

When DC voltage sources are connected in series aiding (positive terminal to negative terminal), their individual voltages add together directly. Four

1.5\text{ V}

cells in series provide a total electromotive force of

4 \times 1.5\text{ V} = 6.0\text{ V}

Step-by-Step Solution

Identify the circuit configuration and the formula for total EMF in series.

E_{\text{total}} = E_1 + E_2 + E_3 + E_4

When electrical power sources (cells) are wired in series aiding, their individual voltages add directly together to produce the total potential difference.

Sum the voltages of the four identical

1.5\text{ V}

cells.

E_{\text{total}} = 1.5\text{ V} + 1.5\text{ V} + 1.5\text{ V} + 1.5\text{ V} = 6.0\text{ V}

Multiplying the cell voltage by the total number of cells (

4 \times 1.5\text{ V}

) yields the total electromotive force.

Key Concept

Series Cell Electromotive Force (EMF) Addition

Estimated Time:45s

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