Question

Difficulty: HardFactoring Polynomials

Consider the polynomial 8x2−10x−38x^2 - 10x - 3. When this expression is factored completely into the form (4x+a)(2x−b)(4x + a)(2x - b), where aa and bb are positive integers, what are the corresponding values for aa and bb?

Answer:The value of aa is 【1】 and the value of bb is 【3】.

Answer

The value of a is 1 and the value of b is 3.
By applying the AC method, the quadratic 8x2−10x−38x^2 - 10x - 3 can be rewritten as 8x2−12x+2x−38x^2 - 12x + 2x - 3 and factored by grouping into 4x(2x−3)+1(2x−3)=(4x+1)(2x−3)4x(2x - 3) + 1(2x - 3) = (4x + 1)(2x - 3). Aligning this with (4x+a)(2x−b)(4x + a)(2x - b) directly shows that a=1a = 1 and b=3b = 3.

Step-by-Step Solution

1
Identify the type of polynomial and the appropriate factoring method.
The polynomial 8x2−10x−38x^2 - 10x - 3 is a non-monic quadratic trinomial (where the leading coefficient is not 1). We can use the ac-method.
The ac-method involves finding two numbers that multiply to the product of the leading coefficient and the constant term, and add to the middle coefficient.
2
Calculate the ac product and find the target sum.
The product is a×c=8×(−3)=−24a \times c = 8 \times (-3) = -24. The target sum is the middle coefficient, which is −10-10.
These values are required to split the middle term for factoring by grouping.
3
Find two integers that multiply to -24 and add to -10.
The numbers −12-12 and 22 meet these conditions, since (−12)×2=−24(-12) \times 2 = -24 and (−12)+2=−10(-12) + 2 = -10.
This allows us to rewrite the middle term −10x-10x without changing the value of the polynomial.
4
Rewrite the middle term and factor by grouping.
8x2−12x+2x−38x^2 - 12x + 2x - 3. Grouping the terms yields (8x2−12x)+(2x−3)(8x^2 - 12x) + (2x - 3). Factoring out the greatest common factor from each group gives 4x(2x−3)+1(2x−3)4x(2x - 3) + 1(2x - 3).
Grouping transforms the four-term expression into a format where a common binomial factor can be extracted.
5
Factor out the common binomial factor and determine the final values.
Factoring out (2x−3)(2x - 3) leaves (4x+1)(2x−3)(4x + 1)(2x - 3). Comparing this to the given form (4x+a)(2x−b)(4x + a)(2x - b) reveals that a=1a = 1 and b=3b = 3.
Matching the derived factorization with the required format identifies the specific constants requested by the problem.

Key Concept

Factoring non-monic quadratic trinomials using the AC method and grouping.
Rate this question