Question

Difficulty: EasyPrecision Measurement Instruments

While inspecting an engine valvetrain, a mechanic measures the outside diameter of a pushrod using a micrometer graduated in thousandths of an inch. The sleeve displays the major digit 33 and reveals 22 full minor tick marks past the digit. The thimble bevel aligns precisely on the graduation mark 1414. What is the pushrod diameter measurement?

  1. A
    0.314 inch0.314\text{ inch}
  2. B
    0.339 inch0.339\text{ inch}
  3. 0.364 inch0.364\text{ inch}Answer
  4. D
    0.389 inch0.389\text{ inch}

Answer

The measured pushrod diameter is 0.364 inch0.364\text{ inch}.
The total reading is obtained by combining the major sleeve increment of 0.300 inch0.300\text{ inch}, the two visible minor subdivision marks (2×0.025 in.=0.050 inch2 \times 0.025\text{ in.} = 0.050\text{ inch}), and the thimble graduation of 0.014 inch0.014\text{ inch}, resulting in 0.300+0.050+0.014=0.364 inch0.300 + 0.050 + 0.014 = 0.364\text{ inch}.

Step-by-Step Solution

1
Read the largest visible major number on the sleeve and multiply by 0.100 inch0.100\text{ inch}.
3×0.100 in.=0.300 inch3 \times 0.100\text{ in.} = 0.300\text{ inch}
Each numbered graduation line along the sleeve represents one-tenth (0.1000.100) of an inch.
2
Count the visible minor subdivision marks between the major digit and the thimble edge, multiplying by 0.025 inch0.025\text{ inch}.
2×0.025 in.=0.050 inch2 \times 0.025\text{ in.} = 0.050\text{ inch}
Each subdivision line represents one complete turn of the thimble, equal to 0.025 inch0.025\text{ inch}.
3
Read the thimble graduation mark that aligns with the sleeve index line and multiply by 0.001 inch0.001\text{ inch}.
14×0.001 in.=0.014 inch14 \times 0.001\text{ in.} = 0.014\text{ inch}
The thimble is divided into 25 equal increments of one-thousandth (0.0010.001) of an inch each.
4
Calculate the total measurement by adding the three individual scale readings together.
0.300+0.050+0.014=0.364 inch0.300 + 0.050 + 0.014 = 0.364\text{ inch}
The final reading is the sum of the sleeve major reading, sleeve minor increments, and the aligned thimble value.

Key Concept

Reading a standard inch outside micrometer by summing the major sleeve divisions (0.100 in.0.100\text{ in.}), minor sleeve subdivisions (0.025 in.0.025\text{ in.}), and thimble graduations (0.001 in.0.001\text{ in.}).
Estimated Time:45s
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