Two workers, Worker X and Worker Y, are carrying a heavy motor block using a rigid, -foot wooden beam. Each worker supports one end of the beam on their shoulder. The motor block weighs pounds. Assume the weight of the beam is negligible. If the center of the motor block is placed on the beam exactly feet away from Worker X, how much of the block's weight is Worker Y supporting?
- poundsAnswer
- Bpounds
- Cpounds
- Dpounds
Answer
Worker Y is supporting pounds of the motor block's weight.
The system is in static equilibrium. By setting Worker X as the pivot point (fulcrum), the motor block creates a downward torque of . To keep the beam from rotating, Worker Y must exert an equal opposing torque at a distance of feet (the entire length of the beam). Therefore, Worker Y's force is . Because Worker Y is four times further from the load than Worker X is, Worker Y carries one-fourth of the weight.
Step-by-Step Solution
Key Concept
Load distribution and static equilibrium (torques/moments)