Question

Difficulty: MediumLoad Distribution and Balancing

Two workers, Worker X and Worker Y, are carrying a heavy motor block using a rigid, 1212-foot wooden beam. Each worker supports one end of the beam on their shoulder. The motor block weighs 300300 pounds. Assume the weight of the beam is negligible. If the center of the motor block is placed on the beam exactly 33 feet away from Worker X, how much of the block's weight is Worker Y supporting?

  1. 7575 poundsAnswer
  2. B
    100100 pounds
  3. C
    150150 pounds
  4. D
    225225 pounds

Answer

Worker Y is supporting 7575 pounds of the motor block's weight.
The system is in static equilibrium. By setting Worker X as the pivot point (fulcrum), the motor block creates a downward torque of 300 pounds×3 feet=900 foot-pounds300 \text{ pounds} \times 3 \text{ feet} = 900 \text{ foot-pounds}. To keep the beam from rotating, Worker Y must exert an equal opposing torque at a distance of 1212 feet (the entire length of the beam). Therefore, Worker Y's force is 900÷12=75 pounds900 \div 12 = 75 \text{ pounds}. Because Worker Y is four times further from the load than Worker X is, Worker Y carries one-fourth of the weight.

Step-by-Step Solution

1
Identify the pivot point and the forces acting on the beam.
Let Worker X's shoulder be the pivot point. The forces are the 300300-pound downward load acting at a distance of 33 feet, and Worker Y's upward supporting force acting at a distance of 1212 feet.
Setting one end as the pivot point allows us to isolate the unknown force at the other end using the principle of torque (moments).
2
Set up the static equilibrium equation where total torque equals zero.
The downward torque from the block must equal the upward torque from Worker Y: 300×3=FY×12300 \times 3 = F_Y \times 12.
For the beam to be balanced and not rotate, the clockwise moments and counter-clockwise moments around the pivot must be equal.
3
Solve the equation for Worker Y's supporting force (FYF_Y).
900=12×FY900 = 12 \times F_Y, which simplifies to FY=900/12=75F_Y = 900 / 12 = 75 pounds.
Basic algebra is used to isolate the unknown variable.

Key Concept

Load distribution and static equilibrium (torques/moments)
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