A technician is troubleshooting an industrial robotics controller that delivers direct cur… — Armed Services Vocational Aptitude Battery (ASVAB)

A technician is troubleshooting an industrial robotics controller that delivers direct current (DC) to a solid-state indicator module. The module has an internal resistance of $1.5\text{ k}\Omega$ . When the circuit is energized, a voltmeter measures a potential difference of $24\text{ V}$ across the module. What is the current flowing through the indicator module?

A
$16\text{ A}$
B
$36\text{ mA}$
$16\text{ mA}$ Answer
D
$62.5\text{ mA}$

Answer

The current flowing through the indicator module is

16\text{ mA}

According to Ohm's Law, current equals voltage divided by resistance (

I = \frac{V}{R}

). Converting the resistance of

1.5\text{ k}\Omega

to base ohms gives

1{}500\text{ }\Omega

. Dividing the voltage of

24\text{ V}

1{}500\text{ }\Omega

yields

0.016\text{ A}

, which converts to

16\text{ mA}

Step-by-Step Solution

Convert the resistance from kilo-ohms to base ohms

R = 1.5\text{ k}\Omega = 1.5 \times 10^3\text{ }\Omega = 1{}500\text{ }\Omega

Standard electrical calculations using Ohm's Law require values in fundamental SI units (volts, amperes, ohms).

Apply Ohm's Law to calculate the current in amperes

I = \frac{V}{R} = \frac{24\text{ V}}{1{}500\text{ }\Omega} = 0.016\text{ A}

Ohm's Law states that current equals electromotive force (voltage) divided by resistance.

Convert the resulting current from amperes to milliamperes

I = 0.016\text{ A} \times 1{}000\text{ mA/A} = 16\text{ mA}

Expressing fractional amperes in milliamperes aligns with standard instrumentation and option specifications.

Key Concept

Ohm's Law (

I = \frac{V}{R}

) and metric prefix conversion (kilo- and milli-).

Estimated Time:1m 0s

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