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Difficulty: MediumTransistors

In a bipolar junction transistor (BJT) amplifier circuit operating in its active region, a base current (IBI_B) of 2 mA2\text{ mA} is applied. If the transistor has a common-emitter DC current gain (β\beta or hFEh_{FE}) of 5050, what is the resulting collector current (ICI_C) flowing through the transistor?

  1. A
    25 mA25\text{ mA}
  2. B
    52 mA52\text{ mA}
  3. 100 mA100\text{ mA}Answer
  4. D
    0.04 mA0.04\text{ mA}

Answer

The collector current (ICI_C) is 100 mA100\text{ mA}.
In the active region of a bipolar junction transistor, the collector current is directly proportional to the base current by the factor of DC current gain: IC=β×IBI_C = \beta \times I_B. Multiplying the base current of 2 mA2\text{ mA} by the gain of 5050 yields 100 mA100\text{ mA}.

Step-by-Step Solution

1
Identify the given values and formula for transistor DC current gain in the active region.
Given IB=2 mAI_B = 2\text{ mA} and β=50\beta = 50. The governing formula is IC=β×IBI_C = \beta \times I_B.
Current gain (β\beta) represents the amplification factor between the controlling base current and the controlled collector current.
2
Substitute the measured base current and gain into the current equation.
IC=50×2 mA=100 mAI_C = 50 \times 2\text{ mA} = 100\text{ mA}.
Calculating the product gives the total current flowing through the collector terminal.

Key Concept

Bipolar Junction Transistor DC Current Gain (β\beta or hFEh_{FE})
Estimated Time:1m 0s
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Topics

Transistors

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