Question

Difficulty: MediumVoltage and Electromotive Force (EMF)

A series-connected thermopile module contains 1414 thermocouple junctions. If each junction generates an electromotive force (EMF) of 350 mV350\text{ mV} when heated, what is the total output potential difference of the module in volts (V\text{V})?

Answer: 4.9 V

Answer

The total output potential difference is 4.9 V4.9\text{ V}.
Because all 1414 thermocouple junctions are connected in series aiding, their individual voltages sum directly: 14×350 mV=4900 mV14 \times 350\text{ mV} = 4{}900\text{ mV}. Converting millivolts to volts by dividing by 10001{}000 yields exactly 4.9 V4.9\text{ V}.

Step-by-Step Solution

1
Calculate the total series electromotive force in millivolts
Etotal=14×350 mV=4900 mVE_{\text{total}} = 14 \times 350\text{ mV} = 4{}900\text{ mV}
When voltage sources or EMF-generating elements are connected in a series-aiding string, their individual electromotive forces add directly.
2
Convert the total potential difference from millivolts to standard volts
V=4900 mV1000 mV/V=4.9 VV = \frac{4{}900\text{ mV}}{1{}000\text{ mV/V}} = 4.9\text{ V}
The metric prefix 'milli-' indicates one thousandth (10−310^{-3}) of a base unit, requiring division by 10001{}000 to convert millivolts to volts.

Key Concept

Series electromotive forces (EMFs) add algebraically in a series-aiding configuration, and millivolts convert to standard volts by a factor of 10−310^{-3} (1000 mV=1 V1{}000\text{ mV} = 1\text{ V}).
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