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Difficulty: EasyWork, Energy, and Power

A warehouse worker applies a constant horizontal force of 75 N75\text{ N} to push a supply crate a distance of 8 meters8\text{ meters} across a smooth floor. What is the total amount of work done on the crate?

  1. A
    83 J83\text{ J}
  2. 600 J600\text{ J}Answer
  3. C
    600 W600\text{ W}
  4. D
    9.38 J9.38\text{ J}

Answer

600 J600\text{ J}
Mechanical work is calculated using the equation W=F×dW = F \times d, where FF is the applied force in Newtons and dd is the displacement in meters. Multiplying 75 N75\text{ N} by 8 m8\text{ m} gives 600 Joules600\text{ Joules} (J\text{J}).

Step-by-Step Solution

1
Identify the given physical quantities and the formula for mechanical work.
Force F=75 NF = 75\text{ N}, distance d=8 md = 8\text{ m}, and work formula W=F×dW = F \times d.
Work is defined in physics as the product of the force applied to an object and the distance through which the force acts in the direction of motion.
2
Multiply the force by the distance to calculate the work done.
W=75 N×8 m=600 JW = 75\text{ N} \times 8\text{ m} = 600\text{ J}
One Joule (J\text{J}) is equal to one Newton-meter (N⋅m\text{N}\cdot\text{m}).

Key Concept

Work is equal to force multiplied by displacement in the direction of the force (W=FdW = Fd), measured in Joules.
Estimated Time:45s
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Topics

Work, Energy, and Power

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