Examkin

Question

Difficulty: EasyOscilloscopes

An oscilloscope displays a periodic alternating voltage waveform on its screen. One complete cycle of the waveform occupies 4 horizontal divisions4\text{ horizontal divisions} across the graticule. If the oscilloscope's horizontal time base (Time/Div) control is set to 15 ms/div15\text{ ms/div}, what is the period of the waveform in milliseconds?

Answer: 60 ms

Answer

60 ms60\text{ ms}
The period (TT) of a signal displayed on an oscilloscope is found by multiplying the number of horizontal divisions for one complete cycle by the Time/Div control setting: 4 divisions×15 ms/div=60 ms4\text{ divisions} \times 15\text{ ms/div} = 60\text{ ms}.

Step-by-Step Solution

1
Identify the number of horizontal graticule divisions occupied by one full waveform cycle.
4 divisions4\text{ divisions}
On an oscilloscope display, the horizontal axis represents time, and one full cycle corresponds to the period (TT).
2
Multiply the division count by the horizontal scale factor (15 ms/div15\text{ ms/div}).
4 div×15 ms/div=60 ms4\text{ div} \times 15\text{ ms/div} = 60\text{ ms}
Multiplying the span in divisions by the time allocated per division gives the total duration of one cycle.

Key Concept

Calculating waveform period from oscilloscope horizontal division settings
Estimated Time:45s
Rate this question

Topics

Oscilloscopes

More questions from this topic