A heavy steel transport barge leaves the salty water of an ocean bay and enters a freshwater river. The total weight of the barge and its cargo remains exactly the same. Given that saltwater has a significantly higher density than freshwater, how will the depth that the barge sinks into the water (its draft) change, and why?
- It will sink deeper into the water, because it must displace a larger volume of the less-dense freshwater to equal its own weight.Answer
- BIts draft will remain exactly the same, because the required buoyant force depends entirely on the barge's total weight, which has not changed.
- CIt will float higher in the water, because the lighter freshwater pushes upward against the hull with a greater pressure.
- DIt will sink deeper into the water, because the lack of salt in the river water causes the barge's overall mass to increase.
Answer
The barge will sink deeper into the water because it must displace a larger volume of the less-dense freshwater to equal its own weight.
According to Archimedes' principle, a floating object displaces a weight of fluid equal to its own true weight. Because the barge's weight is constant, it must displace the exact same *weight* of water in both locations to stay afloat. Since freshwater is less dense (weighs less per unit of volume) than saltwater, a larger physical *volume* of freshwater must be displaced to equal the barge's massive weight. To displace more volume, the barge must sink deeper into the water, increasing its draft.
Step-by-Step Solution
Key Concept
Buoyancy and floating equilibrium (Archimedes' Principle)
Estimated Time:1m 0s