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Difficulty: MediumCargo Securement: Tie-Down Rules and WLL

A commercial driver is transporting a single unblocked industrial air compressor unit on an open flatbed trailer. The cargo measures 12 feet12\text{ feet} in length and weighs 16,000 pounds16,000\text{ pounds}. Securing this load using three indirect tie-downs, each with a Working Load Limit (WLL) of 3,335 pounds3,335\text{ pounds}, satisfies both the minimum tie-down count and aggregate Working Load Limit requirements under federal CDL cargo securement regulations.

Answer: Answer

Answer

True, because the securement satisfies both the length-based minimum tie-down rule and the aggregate Working Load Limit requirement.
The securement arrangement meets all legal mandates: the three tie-downs satisfy the unblocked length requirement (22 tie-downs for the first 10 feet+110\text{ feet} + 1 tie-down for the remaining 2 feet2\text{ feet}), and the aggregate WLL of 10,005 pounds10,005\text{ pounds} (3×3,335 pounds3 \times 3,335\text{ pounds}) exceeds the required 50%50\% threshold of 8,000 pounds8,000\text{ pounds}.

Step-by-Step Solution

1
Determine the minimum number of tie-downs required based on cargo length and blocking status.
Three tie-downs are required.
For unblocked cargo, regulations mandate two tie-downs for the first 10 feet10\text{ feet} of length plus one additional tie-down for each additional 10 feet10\text{ feet} or fraction thereof. For 12 feet12\text{ feet}, the requirement is 2+1=32 + 1 = 3 tie-downs.
2
Calculate the minimum required aggregate Working Load Limit (WLL) based on cargo weight.
Minimum Required WLL=0.50×16,000 pounds=8,000 pounds\text{Minimum Required WLL} = 0.50 \times 16,000\text{ pounds} = 8,000\text{ pounds}.
Federal regulations require the aggregate WLL of all tie-downs to equal at least one-half (50%50\%) of the total cargo weight.
3
Calculate the actual aggregate WLL provided by the rigging and compare with both regulatory thresholds.
Actual Aggregate WLL=3×3,335 pounds=10,005 pounds\text{Actual Aggregate WLL} = 3 \times 3,335\text{ pounds} = 10,005\text{ pounds}.
Since three tie-downs are used (3≥33 \geq 3) and the total WLL of 10,005 pounds10,005\text{ pounds} exceeds the required 8,000 pounds8,000\text{ pounds}, the securement arrangement fully complies with all regulations.

Key Concept

Cargo securement on flatbed trailers requires satisfying two independent criteria: a minimum tie-down count based on article length and blocking status, and an aggregate Working Load Limit of at least 50%50\% of the cargo weight.
Estimated Time:1m 0s
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Topics

Cargo Securement: Tie-Down Rules and WLL

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