Question

Difficulty: HardStopping Distance Components

During a post-collision event data analysis on a dry, level highway, telematics indicate that a fully loaded commercial motor vehicle equipped with air brakes was traveling at a steady speed of 60 mph60\text{ mph} (88 ft/s88\text{ ft/s}). The driver required 1.75 seconds1.75\text{ seconds} to perceive a roadway hazard, 0.75 seconds0.75\text{ seconds} to physically apply the foot brake, experienced the typical 0.5 second0.5\text{ second} air brake lag before the brakes engaged, and the vehicle required 250 feet250\text{ feet} of actual braking distance to come to a halt. What is the total stopping distance required for this vehicle from the initial perception of the hazard to a complete stop?

  1. A
    470 feet470\text{ feet}
  2. 514 feet514\text{ feet}Answer
  3. C
    360 feet360\text{ feet}
  4. D
    294 feet294\text{ feet}

Answer

514 feet514\text{ feet}
Total stopping distance for an air-brake equipped commercial motor vehicle is composed of four distinct sequential components: Perception Distance + Reaction Distance + Brake Lag Distance + Braking Distance. At a speed of 60 mph60\text{ mph} (88 ft/s88\text{ ft/s}), the vehicle travels 154 feet154\text{ feet} during perception (1.75 s1.75\text{ s}), 66 feet66\text{ feet} during reaction (0.75 s0.75\text{ s}), 44 feet44\text{ feet} during air brake lag (0.5 s0.5\text{ s}), and 250 feet250\text{ feet} during active braking. Adding these four values together (154 ft+66 ft+44 ft+250 ft154\text{ ft} + 66\text{ ft} + 44\text{ ft} + 250\text{ ft}) results in a total stopping distance of 514 feet514\text{ feet}.

Step-by-Step Solution

1
Calculate the perception distance traveled during the 1.75 second1.75\text{ second} hazard recognition interval.
1.75 s×88 ft/s=154 feet1.75\text{ s} \times 88\text{ ft/s} = 154\text{ feet}
Perception distance is the distance traveled from the instant the hazard becomes visible until the driver's brain recognizes it.
2
Calculate the reaction distance traveled during the 0.75 second0.75\text{ second} pedal movement interval.
0.75 s×88 ft/s=66 feet0.75\text{ s} \times 88\text{ ft/s} = 66\text{ feet}
Reaction distance is the distance traveled while the driver moves their foot from the accelerator to the brake pedal.
3
Calculate the brake lag distance traveled during the 0.5 second0.5\text{ second} pneumatic activation delay.
0.5 s×88 ft/s=44 feet0.5\text{ s} \times 88\text{ ft/s} = 44\text{ feet}
Commercial vehicles equipped with air brakes experience a mechanical delay of approximately half a second for air pressure to reach the brake chambers and engage the drums.
4
Sum all four components (perception, reaction, brake lag, and braking distance) to determine the total stopping distance.
154 ft+66 ft+44 ft+250 ft=514 feet154\text{ ft} + 66\text{ ft} + 44\text{ ft} + 250\text{ ft} = 514\text{ feet}
Total stopping distance for air brake vehicles is the comprehensive sum of all human and mechanical phases required to bring the vehicle to a full stop.

Key Concept

Four Components of Total Stopping Distance for Air Brake Commercial Vehicles
Estimated Time:1m 30s
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