Question

Difficulty: HardHours of Service (HOS) Regulations

After completing the required 1010 consecutive hours off duty, a commercial freight driver begins a work shift at 06:0006:00. The driver's activities throughout the day are recorded as follows:

* 06:00−07:0006:00 - 07:00: Pre-trip vehicle inspection and cargo loading (1.0 hour1.0\text{ hour} on duty, not driving)
* 07:00−11:3007:00 - 11:30: Driving (4.5 hours4.5\text{ hours} driving)
* 11:30−12:0011:30 - 12:00: Meal break (0.5 hours0.5\text{ hours} off duty)
* 12:00−15:3012:00 - 15:30: Driving (3.5 hours3.5\text{ hours} driving)
* 15:30−17:3015:30 - 17:30: Shipper dock delay (2.0 hours2.0\text{ hours} on duty, not driving)

Assuming no adverse driving conditions apply, what is the maximum number of driving hours remaining for this shift, and by what exact time must driving cease?

  1. A
    3.0 hours3.0\text{ hours}, with all driving ending by 20:3020:30
  2. 2.5 hours2.5\text{ hours}, with all driving ending by 20:0020:00Answer
  3. C
    3.0 hours3.0\text{ hours}, with all driving ending by 20:0020:00
  4. D
    1.5 hours1.5\text{ hours}, with all driving ending by 19:0019:00

Answer

2.5 hours2.5\text{ hours}, with all driving ending by 20:0020:00
The shift began at 06:00, making the 14-hour consecutive duty window expire precisely at 20:00. At 17:30, only 2.5 hours remain before this cutoff. Although the driver has driven 8.0 hours and has 3.0 hours left under the 11-hour driving limit, the 14-hour window takes precedence, limiting the driver to 2.5 hours of driving, all of which must end by 20:00.

Step-by-Step Solution

1
Calculate cumulative driving hours completed and remaining capacity under the 11-hour driving rule.
Accumulated driving =4.5 hours+3.5 hours=8.0 hours= 4.5\text{ hours} + 3.5\text{ hours} = 8.0\text{ hours}. Remaining driving capacity =11.0−8.0=3.0 hours= 11.0 - 8.0 = 3.0\text{ hours}.
Property-carrying drivers are permitted a maximum of 11 hours of driving following 10 consecutive hours off duty.
2
Calculate the expiration time of the 14-hour consecutive driving window.
Window start time is 06:0006:00; expiration is 06:00+14 hours=20:0006:00 + 14\text{ hours} = 20:00.
The 14-hour consecutive duty window starts when the driver comes on duty and runs continuously regardless of off-duty breaks or dock delays.
3
Determine the remaining time available inside the 14-hour window from the current time (17:3017:30).
Available window time =20:00−17:30=2.5 hours= 20:00 - 17:30 = 2.5\text{ hours}.
No driving is permitted after the 14th consecutive hour from coming on duty.
4
Apply the most restrictive limit between remaining driving capacity and remaining duty window time.
min⁡(3.0 hours driving limit,2.5 hours window limit)=2.5 hours\min(3.0\text{ hours driving limit}, 2.5\text{ hours window limit}) = 2.5\text{ hours}, ending at 20:0020:00.
Even though 3.0 hours remain under the 11-hour driving rule, the 14-hour window limits driving to at most 2.5 hours before 20:00.

Key Concept

Interaction between the 11-hour maximum driving limit and the non-extendable 14-hour consecutive duty window.
Estimated Time:2m 0s
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