A driver secures a crated diesel generator weighing 16{}000\text{ pounds} and measuring 8\… — Commercial Driver's License (CDL) General Knowledge Exam

A driver secures a crated diesel generator weighing $16{}000\text{ pounds}$ and measuring $8\text{ feet}$ in length on an open flatbed trailer with no forward bulkhead or blocking. Fastening the crate with $2\text{ indirect tie-downs}$ , each having a Working Load Limit (WLL) of $3{}500\text{ pounds}$ , satisfies the minimum federal CDL securement requirements.

Answer: Answer

Answer

False

The statement is false because the rigging provides an aggregate Working Load Limit of only

7{}000\text{ pounds}

(

2 \times 3{}500\text{ pounds}

), which is deficient by

1{}000\text{ pounds}

from the required

50\%

threshold of

8{}000\text{ pounds}

for a

16{}000\text{-pound}

cargo item.

Step-by-Step Solution

Determine the minimum number of tie-downs required based on cargo length and blocking condition.

Cargo that is unblocked and measures between

5\text{ feet}

and

10\text{ feet}

in length requires at least

2\text{ tie-downs}

Federal CDL cargo securement standards mandate a minimum of

2\text{ tie-downs}

for any unblocked article longer than

5\text{ feet}

regardless of weight.

Calculate the required aggregate Working Load Limit (WLL) based on cargo weight.

\text{Required WLL} = 16{}000\text{ pounds} \times 0.50 = 8{}000\text{ pounds}

Federal regulations mandate that the aggregate WLL of all tie-downs combined must equal at least one-half (

50\%

) of the total cargo weight.

Calculate the aggregate WLL provided by the rigging and compare it against the required threshold.

\text{Provided WLL} = 2 \times 3{}500\text{ pounds} = 7{}000\text{ pounds}

, which is less than the required

8{}000\text{ pounds}

Because the provided aggregate WLL (

7{}000\text{ pounds}

) falls short of the required

8{}000\text{ pounds}

, the securement does not meet legal standards.

Key Concept

Cargo Securement: Minimum Tie-Down Count and Aggregate Working Load Limit (WLL)

Estimated Time:1m 0s

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