A commercial driver is transporting a 9\text{-foot} long piece of industrial crated equipm… — Commercial Driver's License (CDL) General Knowledge Exam

A commercial driver is transporting a $9\text{-foot}$ long piece of industrial crated equipment weighing $14{}000\text{ pounds}$ on a flatbed trailer, positioned securely against a front-end headboard to prevent forward movement. Securing this load with two indirect tie-downs that pass over the top of the crate to opposite anchor rails, each having a Working Load Limit ( $\text{WLL}$ ) of $3{}500\text{ pounds}$ , fully meets both the federal length-based minimum tie-down quantity rule and the minimum aggregate Working Load Limit requirement.

Answer: Answer

Answer

True

The statement accurately reflects federal cargo securement standards: cargo prevented from forward movement by a headboard requires only one tie-down per

10\text{ feet}

(or fraction thereof), and two indirect tie-downs rated at

3{}500\text{ pounds}

provide an aggregate capacity of

7{}000\text{ pounds}

, which matches the required

50\%

of the

14{}000\text{-pound}

cargo weight.

Step-by-Step Solution

Evaluate the length-based tie-down requirement under blocked cargo regulations.

Minimum 1 tie-down required; 2 tie-downs are provided, satisfying the rule.

Under federal cargo securement rules (FMCSA § 393.110), an article of cargo that is blocked or braced against a front-end headboard to prevent forward motion requires only one tie-down for every

10\text{ feet}

of length or fraction thereof. For a

9\text{-foot}

article, at least one tie-down is required.

Calculate the required aggregate Working Load Limit (WLL) based on cargo weight.

Required aggregate

\text{WLL} = 7{}000\text{ pounds}

Federal regulations mandate that the aggregate

\text{WLL}

of all tie-downs securing an article against movement must equal at least

50\%

(

1/2

) of the total cargo weight:

14{}000\text{ lbs} \times 0.50 = 7{}000\text{ lbs}

Calculate the effective aggregate WLL provided by the indirect tie-downs.

Aggregate

\text{WLL} = 7{}000\text{ pounds}

When an indirect tie-down passes over the cargo from one side rail to the other, it provides

100\%

of its rated

\text{WLL}

. Two straps rated at

3{}500\text{ lbs}

each provide

2 \times 3{}500\text{ lbs} = 7{}000\text{ lbs}

of aggregate restraint.

Synthesize regulatory requirements to determine full compliance.

The setup satisfies both regulatory criteria simultaneously.

The driver provides two tie-downs (exceeding the one required for a blocked 9-foot load) and achieves an aggregate

\text{WLL}

7{}000\text{ lbs}

(meeting the required

50\%

14{}000\text{ lbs}

Key Concept

Cargo Securement: Blocked vs. Unblocked Tie-Down Counts and Aggregate Working Load Limit (WLL)

Estimated Time:1m 30s

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