Question

Difficulty: MediumCargo Securement: Tie-Down Rules and WLL

A driver is transporting a single unblocked bundle of commercial timber on a flatbed trailer. The cargo measures 18 feet18\text{ feet} in length and has a total weight of 16,000 pounds16,000\text{ pounds}. The driver is using indirect tie-downs (webbing straps passing over the cargo and anchoring on both sides of the trailer), each with a Working Load Limit (WLL) of 3,000 pounds3,000\text{ pounds}. According to Federal Motor Carrier Safety Administration (FMCSA) cargo securement standards, what is the minimum number of tie-downs required to legally secure this load?

  1. A
    1 tie-down
  2. B
    2 tie-downs
  3. 3 tie-downsAnswer
  4. D
    6 tie-downs

Answer

3 tie-downs are required to legally secure the cargo.
Federal Motor Carrier Safety Administration (FMCSA) cargo securement standards require drivers to satisfy two independent criteria: cargo length and aggregate Working Load Limit (WLL). Based on length, an unblocked 18-foot18\text{-foot} item requires at least 2 tie-downs (1 tie-down per 10 feet10\text{ feet} or fraction thereof). Based on weight, the aggregate WLL must equal at least 50%50\% of the total cargo weight (0.50×16,000 lbs=8,000 lbs0.50 \times 16,000\text{ lbs} = 8,000\text{ lbs}). Two straps rated at 3,000 lbs3,000\text{ lbs} each provide only 6,000 lbs6,000\text{ lbs} of aggregate WLL, which is insufficient. Therefore, a minimum of 3 straps providing 9,000 lbs9,000\text{ lbs} of aggregate WLL is required to satisfy both regulations.

Step-by-Step Solution

1
Determine the minimum number of tie-downs required based on cargo length and blocking status.
For an unblocked article of cargo measuring 18 feet18\text{ feet}, regulations require at least 1 tie-down for the first 10 feet10\text{ feet} and 1 tie-down for each additional 10 feet10\text{ feet} or fraction thereof, resulting in a minimum of 2 tie-downs.
Cargo securement rules specify a baseline number of tie-downs based on dimensions to prevent shifting and rotation.
2
Calculate the required aggregate Working Load Limit (WLL) based on total cargo weight.
Required WLL=50%×16,000 lbs=8,000 lbs\text{Required WLL} = 50\% \times 16,000\text{ lbs} = 8,000\text{ lbs}.
Federal regulations mandate that the aggregate WLL of all securement devices must equal at least half of the total weight of the cargo.
3
Calculate the number of 3,000-pound3,000\text{-pound} rated straps needed to meet the aggregate WLL requirement.
8,000 lbs3,000 lbs/strap=2.67 straps→3 straps\frac{8,000\text{ lbs}}{3,000\text{ lbs/strap}} = 2.67\text{ straps} \rightarrow 3\text{ straps} (aggregate WLL =9,000 lbs= 9,000\text{ lbs}).
Because tie-down counts must be whole numbers and satisfy both length and weight mandates, the larger requirement governs.

Key Concept

Tie-Down Rules and Aggregate Working Load Limit (WLL)
Estimated Time:1m 15s
Rate this question