Question

Difficulty: Very hardStopping Distance Components

A safety auditor is calculating the stopping requirements for an air-braked tanker traveling at exactly 45 mph45\text{ mph} (66 ft/s66\text{ ft/s}) under ideal conditions. The auditor determines that the mechanical braking distance (the distance traveled after the brake linings physically engage) is exactly 105 feet105\text{ feet}.

Using the standard CDL manual parameters for human perception time, human reaction time, and air brake lag time, what is the total stopping distance of the tanker in feet?

Answer: 303 feet

Answer

303 feet
The total stopping distance for an air-braked vehicle consists of four components: perception distance, reaction distance, brake lag distance, and braking distance. By applying standard CDL parameters, the driver requires 1.75 seconds to perceive the hazard and 0.75 seconds to react, while the air brake system takes an additional 0.5 seconds to actuate. This creates a total pre-braking delay of 3.0 seconds. At a velocity of 66 ft/s, the vehicle travels 198 feet during this delay. Adding this to the 105-foot mechanical braking distance yields a total stopping distance of 303 feet.

Step-by-Step Solution

1
Identify the standard time delays for a commercial driver and air brake system.
Perception time = 1.75s, Reaction time = 0.75s, Air brake lag = 0.5s.
These constants form the foundation of the CDL stopping distance formula.
2
Calculate the total time elapsed before the vehicle begins mechanically braking.
1.75s + 0.75s + 0.5s = 3.0 seconds.
Combining the delays simplifies the distance calculation.
3
Multiply the vehicle's speed in feet per second by the total pre-braking time.
66×3.0=19866 \times 3.0 = 198 feet.
Distance equals rate multiplied by time (d=vtd = vt).
4
Add the pre-braking distance to the mechanical braking distance.
198+105=303198 + 105 = 303 feet.
Total stopping distance is the sum of all individual distance components.

Key Concept

Total Stopping Distance for Air-Braked Commercial Vehicles
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