A network engineer is deploying IPv6 across an enterprise LAN using Stateless Address Auto… — CompTIA Network+

A network engineer is deploying IPv6 across an enterprise LAN using Stateless Address Autoconfiguration (SLAAC). A client workstation on the subnet has the physical MAC address $00:14:22:01:23:45$ . Which of the following represents the correct 64-bit interface identifier generated for this host using the modified EUI-64 format?

0214:22ff:fe01:2345Answer
B
0014:22ff:fe01:2345
C
0214:22ff:ff01:2345
D
0114:22ff:fe01:2345

Answer

0214:22ff:fe01:2345

The interface identifier '0214:22ff:fe01:2345' correctly follows the modified EUI-64 conversion procedure. The MAC address 00:14:22:01:23:45 is divided into two 24-bit halves (00:14:22 and 01:23:45), the 16-bit hex string FFFE is inserted in the middle, and the 7th bit (Universal/Local bit) of the first byte is inverted from 0 to 1 (changing 0x00 to 0x02).

Step-by-Step Solution

Split the 48-bit MAC address into two 24-bit halves.

The left half is

00:14:22

and the right half is

01:23:45

Modified EUI-64 formatting requires inserting a 16-bit delimiter into the middle of the MAC address.

Insert the hex value

FFFE

between the two halves.

The combined 64-bit value becomes

0014:22FF:FE01:2345

IEEE EUI-64 specifications define

FFFE

as the expansion sequence to turn a 48-bit MAC address into a 64-bit identifier.

Invert the Universal/Local (U/L) bit, which is the 7th bit of the first byte.

The first byte

00_{16}

(

00000000_2

) with its 7th bit inverted becomes

02_{16}

(

00000010_2

), giving

0214:22ff:fe01:2345

Inverting the U/L bit designates that the generated EUI-64 IPv6 interface identifier is derived from a globally unique IEEE MAC address.

Key Concept

Modified EUI-64 Interface Identifier Generation

Estimated Time:1m 30s

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