In an enterprise network running standard IEEE 802.1D Spanning Tree Protocol (STP), Switch-1 serves as the Root Bridge. Two non-root switches, Switch-2 and Switch-3, are directly connected to each other over a point-to-point Gigabit Ethernet link via port FastEthernet 0/1 on both switches. Both Switch-2 and Switch-3 have an identical Root Path Cost of 19. Switch-2 has a Bridge ID of 32768:00-11-22-AA-BB-CC, while Switch-3 has a Bridge ID of 32768:00-11-22-11-22-33. Which switch interface will be elected as the Designated Port for this inter-switch link segment and remain in the Forwarding state?
- Switch-3 FastEthernet 0/1, because both switches have equal Root Path Costs and Switch-3 has the lower MAC address in its Bridge ID.Answer
- BSwitch-2 FastEthernet 0/1, because Switch-2 has a higher numerical MAC address value which takes precedence during STP tiebreaker evaluation.
- CSwitch-2 FastEthernet 0/1, because it blocks untagged frames when a native VLAN mismatch occurs across the link segment.
- DBoth interfaces enter the Blocking state automatically to isolate traffic and prevent a potential Layer 2 loop on the segment.
Answer
Switch-3 FastEthernet 0/1 is elected as the Designated Port because both switches have equal Root Path Costs () and Switch-3 has the lower MAC address ().
For every network segment, STP must elect one Designated Port that forwards traffic. The election process follows a strict hierarchy: 1) Lowest Root Path Cost, 2) Lowest Sender Bridge ID (Priority + MAC), 3) Lowest Sender Port ID. Since both switches have a Root Path Cost of 19 and identical Bridge Priorities (32768), STP evaluates the MAC addresses. Switch-3's MAC address (00-11-22-11-22-33) is lower than Switch-2's MAC address (00-11-22-AA-BB-CC), making Switch-3's interface the Designated Port in the Forwarding state.
Step-by-Step Solution
Key Concept
STP Designated Port Election and Tiebreaking Rules