A network administrator is configuring a point-to-point interconnect between two core rout… — CompTIA Network+

A network administrator is configuring a point-to-point interconnect between two core routers. The interface on Router A is assigned the IPv4 address $10.200.15.14/30$ . What is the directed broadcast address for this subnet?

Answer: 10.200.15.15

Answer

10.200.15.15

For the

/30

network containing the host IP address

10.200.15.14

, the subnet spans from

10.200.15.12

10.200.15.15

. The address

10.200.15.12

is the network ID,

10.200.15.13

and

10.200.15.14

are usable host addresses, and

10.200.15.15

is the directed broadcast address.

Step-by-Step Solution

Determine the subnet mask and subnet block size from the CIDR notation

/30

prefix corresponds to a subnet mask of

255.255.255.252

, which yields a block size of

4

addresses (

256 - 252 = 4

) in the fourth octet.

Understanding the block size identifies subnet boundaries along increments of 4.

Calculate the network address for the host IP

For the host IP

10.200.15.14

, dividing

14

by the block size

4

gives

3

with a remainder of

2

. The network ID for this block is

10.200.15.12

The network address represents the lowest numerical boundary of the subnet.

Determine the directed broadcast address

The broadcast address is the highest address in the subnet block, which is

10.200.15.12 + 3 = 10.200.15.15

The last IP address in any IPv4 subnet block is reserved as the directed broadcast address.

Key Concept

IPv4 Subnetting and Broadcast Address Calculation

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