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Difficulty: EasyIPv4 Addressing and Subnetting

A network technician is verifying the IP configuration of a workstation with the IPv4 address 192.168.1.68/27192.168.1.68/27. What is the broadcast address for the subnet to which this workstation belongs?

  1. 192.168.1.95192.168.1.95Answer
  2. B
    192.168.1.94192.168.1.94
  3. C
    192.168.1.63192.168.1.63
  4. D
    192.168.1.127192.168.1.127

Answer

The broadcast address for the subnet is 192.168.1.95192.168.1.95.
A /27 CIDR prefix corresponds to a subnet mask of 255.255.255.224, creating subnets in block sizes of 32 in the fourth octet. For host address 192.168.1.68, the network ID is 192.168.1.64 and the next network ID is 192.168.1.96. The broadcast address is the final IP before the next network boundary, which is 192.168.1.95.

Step-by-Step Solution

1
Determine the block size from the CIDR prefix.
A /27 prefix corresponds to subnet mask 255.255.255.224, giving a block size of 256−224=32256 - 224 = 32 addresses in the fourth octet.
Calculating the block size identifies the step increment between network boundaries.
2
Identify the network ID for the host address 192.168.1.68.
Subnet boundaries increment by 32 (0, 32, 64, 96...). The host IP 192.168.1.68 falls into the 192.168.1.64192.168.1.64 subnet block.
Finding the network ID establishes the lower boundary of the subnet.
3
Calculate the broadcast address.
The broadcast address is one less than the next network address (192.168.1.96−1=192.168.1.95192.168.1.96 - 1 = 192.168.1.95).
The broadcast address is always the final address in a subnet block.

Key Concept

IPv4 Subnet Boundaries and Broadcast Address Calculation
Estimated Time:1m 0s
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Topics

IPv4 Addressing and Subnetting

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