Question

Difficulty: HardIPv4 Addressing and Subnetting

An enterprise network operations team is allocating IPv4 subnets from the parent block 172.31.192.0/19172.31.192.0/19 to provision Point-to-Point WAN links between datacenter locations. Each link requires a dedicated subnet configured with a /30/30 mask to connect two router interfaces. If the team provisions 4545 operational Point-to-Point link subnets sequentially starting from the lowest IP address of the parent block, what is the maximum number of additional /30/30 link subnets that can be created from the remaining unallocated space within this /19/19 block?

Answer: 2003 subnets

Answer

The maximum number of additional /30 link subnets that can be created from the remaining unallocated space is 2003.
The parent block has a prefix length of /19 and each link uses a /30 subnet mask. Subtracting the prefix lengths (3019=1130 - 19 = 11) gives 1111 subnet bits, which equals 211=20482^{11} = 2048 total possible /30 subnets within the /19 block. Subtracting the 45 already provisioned subnets leaves 204845=20032048 - 45 = 2003 unallocated /30 subnets.

Step-by-Step Solution

1
Calculate the total number of /30 subnets available within a /19 parent block
2048 subnets
The prefix length difference between the child subnet (/30) and parent block (/19) is 3019=1130 - 19 = 11 bits. The total number of /30 subnets created is 211=20482^{11} = 2048.
2
Subtract the number of already allocated /30 subnets from the total available subnet capacity
2003 subnets
Subtracting the 4545 allocated subnets from the total capacity of 20482048 (204845=20032048 - 45 = 2003) yields the remaining unallocated /30 subnets.

Key Concept

Subnet allocation and capacity calculations using CIDR prefix length differences
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