Question

Difficulty: EasyFunction Definitions, Evaluation, and Custom Operators

For all real numbers aa and bb, the custom operation ⋆\star is defined by a⋆b=(a+b)2−3ba \star b = (a + b)^2 - 3b. What is the value of 4⋆24 \star 2?

  1. 30Answer
  2. B
    24
  3. C
    14
  4. D
    33
  5. E
    18

Answer

30
Substituting a=4a = 4 and b=2b = 2 into the definition (a+b)2−3b(a + b)^2 - 3b gives (4+2)2−3(2)=62−6=36−6=30(4 + 2)^2 - 3(2) = 6^2 - 6 = 36 - 6 = 30.

Step-by-Step Solution

1
Identify the values assigned to the custom operator variables
a=4a = 4 and b=2b = 2
The expression 4⋆24 \star 2 corresponds to evaluating a⋆ba \star b where aa is the first operand and bb is the second operand.
2
Substitute a=4a = 4 and b=2b = 2 into the operator definition (a+b)2−3b(a + b)^2 - 3b
(4+2)2−3(2)(4 + 2)^2 - 3(2)
Direct substitution into the given algebraic definition.
3
Perform the operations in parentheses and exponentiation
62−6=36−66^2 - 6 = 36 - 6
First add inside the parentheses (4+2=64 + 2 = 6), then square the sum (62=366^2 = 36), and multiply 3×2=63 \times 2 = 6.
4
Subtract to find the final value
30
Subtracting 66 from 3636 yields 3030.

Key Concept

Custom Operator Evaluation
Estimated Time:45s
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