Question

Difficulty: MediumRate, Time, and Distance Problems

A commuter travels to work along a straight route at a constant speed of 4040 miles per hour. On the return trip along the exact same route, traffic delays reduce the average speed to 2424 miles per hour. If the return trip takes 4040 minutes longer than the trip to work, what is the total distance, in miles, traveled by the commuter for the round trip?

Answer: 80 miles

Answer

The total distance traveled by the commuter for the round trip is 80 miles.
The total distance for the round trip is 80 miles. By expressing time as distance divided by speed, the outbound trip takes D40\frac{D}{40} hours and the return trip takes D24\frac{D}{24} hours. Since the return trip takes 4040 minutes (23\frac{2}{3} hours) longer, setting up the equation D24D40=23\frac{D}{24} - \frac{D}{40} = \frac{2}{3} yields D=40D = 40 miles for one way. The round-trip distance is 2×40=802 \times 40 = 80 miles.

Step-by-Step Solution

1
Define variables for the one-way distance and expressions for the travel time of each leg.
Let DD represent the one-way distance in miles. Outbound time t1=D40t_1 = \frac{D}{40} hours; return time t2=D24t_2 = \frac{D}{24} hours.
Using the relation Time=DistanceSpeed\text{Time} = \frac{\text{Distance}}{\text{Speed}} expresses time in terms of a single unknown variable.
2
Convert the given time difference from minutes to hours.
40 minutes=4060 hours=23 hours40 \text{ minutes} = \frac{40}{60} \text{ hours} = \frac{2}{3} \text{ hours}.
Speeds are given in miles per hour, so time units must be in hours for dimensional consistency.
3
Formulate the equation representing the time difference and solve for DD.
D24D40=23    2D120=23    D60=23    D=40 miles\frac{D}{24} - \frac{D}{40} = \frac{2}{3} \implies \frac{2D}{120} = \frac{2}{3} \implies \frac{D}{60} = \frac{2}{3} \implies D = 40 \text{ miles}.
Subtracting the faster outbound time from the slower return time equals the time difference.
4
Compute the total distance for the entire round trip.
Total distance=2×D=2×40=80 miles\text{Total distance} = 2 \times D = 2 \times 40 = 80 \text{ miles}.
The question asks for the round-trip distance, which includes both the outbound and return journeys (2D2D).

Key Concept

Rate, Time, and Distance Problems
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