Question

Difficulty: MediumMean, Median, and Mode

A survey asked consumers to rate a new service on a scale from 11 to 55. The table below shows the frequency of each rating received, where kk is a positive integer:

RatingFrequency
14
26
37
4kk
55

If the median rating of all responses is equal to the arithmetic mean of all responses, what is the value of kk?

  1. A
    22
  2. B
    33
  3. 44Answer
  4. D
    55
  5. E
    66

Answer

44
The option stating 44 is correct because with k=4k = 4, the total number of responses is 22+4=2622 + 4 = 26 and the sum of all ratings is 62+4(4)=7862 + 4(4) = 78. The mean is 7826=3\frac{78}{26} = 3. The median of 2626 ordered values is the average of the 13th and 14th values, both of which are 33. Thus, the mean equals the median.

Step-by-Step Solution

1
Calculate total number of data points and total sum in terms of kk
Total responses N=4+6+7+k+5=22+kN = 4 + 6 + 7 + k + 5 = 22 + k. Total sum =1(4)+2(6)+3(7)+4(k)+5(5)=4+12+21+4k+25=62+4k= 1(4) + 2(6) + 3(7) + 4(k) + 5(5) = 4 + 12 + 21 + 4k + 25 = 62 + 4k.
The mean of a frequency distribution is the total weighted sum divided by the total frequency.
2
Determine the median rating
Ratings 1,2,31, 2, 3 account for the first 4+6+7=174 + 6 + 7 = 17 responses. For small positive integer values of kk, the middle position(s) fall within the rating of 33, so the median rating is 33.
Since more than half of the initial 2222 data points are 33 or below (specifically positions 11 through 17 are 3s), the median is 33 for k12k \le 12.
3
Equate the arithmetic mean to the median and solve for kk
\frac{62 + 4k}{22 + k} = 3 \implies 62 + 4k = 3(22 + k) \implies 62 + 4k = 66 + 3k \implies k = 4.
Setting the mean formula equal to the median value of 33 allows solving for kk algebraically.

Key Concept

Weighted Mean and Frequency Distribution Median
Estimated Time:1m 30s
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