Question

Difficulty: EasyRemainders and Units Digit Cyclicity

What is the units digit of 2352^{35}?

  1. A
    2
  2. B
    4
  3. C
    6
  4. 8Answer
  5. E
    0

Answer

The units digit of 2352^{35} is 8.
The units digit of powers of 2 repeats every 4 powers in the sequence 2, 4, 8, 6. Dividing the exponent 35 by 4 yields a quotient of 8 and a remainder of 3. A remainder of 3 corresponds to the third number in the repeating sequence, which is 8.

Step-by-Step Solution

1
Find the cyclicity pattern of the units digits for powers of 2.
The units digits of 21,22,23,24,25,2^1, 2^2, 2^3, 2^4, 2^5, \dots are 2,4,8,6,2,2, 4, 8, 6, 2, \dots, repeating in a cycle of length 4.
Units digits of powers follow a repeating periodic pattern determined by base arithmetic modulo 10.
2
Divide the exponent by the length of the cycle.
35÷4=835 \div 4 = 8 with a remainder of 33.
The remainder indicates how far into the 4-term repeating cycle the exponent 35 reaches.
3
Match the remainder to the corresponding term in the units digit cycle.
A remainder of 3 corresponds to the 3rd term in the cycle (2,4,8,6)(2, 4, 8, 6), which is 8.
The 3rd power in the repeating pattern gives a units digit of 23=82^3 = 8.

Key Concept

Units Digit Cyclicity
Estimated Time:1m 0s
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