Question

Difficulty: EasyExponents, Roots, and Powers of Integers

What is the value of (23+23)2(2^3 + 2^3)^2?

  1. A
    242^4
  2. B
    272^7
  3. 282^8Answer
  4. D
    2122^{12}
  5. E
    2182^{18}

Answer

The correct answer is 282^8.
Combining the terms inside the parentheses gives 23+23=223=242^3 + 2^3 = 2 \cdot 2^3 = 2^4. Squaring 242^4 using the power rule (am)n=amn(a^m)^n = a^{m \cdot n} produces 242=282^{4 \cdot 2} = 2^8.

Step-by-Step Solution

1
Simplify the expression inside the parentheses
23+23=2(23)=2123=242^3 + 2^3 = 2 \cdot (2^3) = 2^1 \cdot 2^3 = 2^4
Adding two identical terms is equivalent to multiplying the term by 2, which allows combining powers of the same base.
2
Apply the power of a power exponent rule to the outer square
(24)2=24×2=28(2^4)^2 = 2^{4 \times 2} = 2^8
When raising a power to another power, multiply the exponents: (am)n=amn(a^m)^n = a^{m \cdot n}.

Key Concept

Combining like exponential terms and applying power rules
Estimated Time:45s
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