Question

Difficulty: EasyLinear Equations in One and Two Variables

If ∣x−5∣=2x−4|x - 5| = 2x - 4, what is the value of xx?

  1. 3Answer
  2. B
    -1
  3. C
    -1 and 3
  4. D
    1
  5. E
    5

Answer

The value of xx is 3.
Solving the absolute value equation yields two candidate values, x=3x = 3 and x=−1x = -1. Substituting x=3x = 3 into the original equation gives ∣3−5∣=2|3 - 5| = 2 and 2(3)−4=22(3) - 4 = 2, which makes the statement true. Therefore, x=3x = 3 is the only valid solution.

Step-by-Step Solution

1
Set up the two cases for the absolute value equation ∣x−5∣=2x−4|x - 5| = 2x - 4.
Case 1: x−5=2x−4x - 5 = 2x - 4; Case 2: x−5=−(2x−4)x - 5 = -(2x - 4).
By definition, ∣a∣=b|a| = b implies a=ba = b or a=−ba = -b when b≥0b \ge 0.
2
Solve Case 1: x−5=2x−4x - 5 = 2x - 4.
x=−1x = -1.
Subtract xx and add 44 to both sides.
3
Solve Case 2: x−5=−2x+4x - 5 = -2x + 4.
3x=9  ⟹  x=33x = 9 \implies x = 3.
Add 2x2x and add 55 to both sides.
4
Test potential solutions in the original equation to eliminate extraneous roots.
For x=−1x = -1: ∣−1−5∣=6≠2(−1)−4=−6|-1 - 5| = 6 \neq 2(-1) - 4 = -6 (Invalid). For x=3x = 3: ∣3−5∣=2=2(3)−4=2|3 - 5| = 2 = 2(3) - 4 = 2 (Valid).
The absolute value of a real number cannot be negative, so the right-hand side 2x−42x - 4 must be non-negative.

Key Concept

Absolute Value Equations and Extraneous Solutions
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