Question

Difficulty: HardOverlapping Sets, Statistics, and Data Distributions

A financial advisory firm manages a portfolio of 9090 assets, each of which is classified as a Tech asset, a Biotech asset, or both. Exactly 5050 of the assets are Tech assets, and exactly 6060 of the assets are Biotech assets. Is the average (arithmetic mean) value of the Tech-only assets greater than the average value of the Biotech-only assets?

(1) The average value of all 5050 Tech assets is $12\$12 million, and the average value of all 6060 Biotech assets is $12\$12 million.
(2) The average value of the 2020 assets classified as both Tech and Biotech assets is $15\$15 million.

  1. A
    Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
  2. B
    Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.Answer
  4. D
    EACH statement ALONE is sufficient.
  5. E
    Statements (1) and (2) TOGETHER are NOT sufficient.

Answer

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Combining both statements allows us to solve for the exact average value of the Tech-only assets (1010 million) and the Biotech-only assets (10.510.5 million). Because we can answer the stem's question with a definitive 'No' (1010 is not greater than 10.510.5), both statements together are sufficient.

Step-by-Step Solution

1
Determine the number of assets in each non-overlapping subgroup using set theory.
Total assets N=90N = 90, Tech assets T=50|T| = 50, Biotech assets B=60|B| = 60. Using TB=T+BTB|T \cup B| = |T| + |B| - |T \cap B|, we get 90=50+60TB    TB=2090 = 50 + 60 - |T \cap B| \implies |T \cap B| = 20. Therefore, Tech-only assets =5020=30= 50 - 20 = 30, Biotech-only assets =6020=40= 60 - 20 = 40, and Both =20= 20.
Rephrasing the question stem into distinct, non-overlapping subset counts simplifies the algebraic system.
2
Evaluate Statement (1) independently.
Let MTM_{T}, MBM_{B}, and MbothM_{both} represent the mean values of Tech-only, Biotech-only, and Both subsets respectively. From Statement (1), total value of Tech =30MT+20Mboth=50×12=600= 30 M_T + 20 M_{both} = 50 \times 12 = 600, and total value of Biotech =40MB+20Mboth=60×12=720= 40 M_B + 20 M_{both} = 60 \times 12 = 720. Subtracting the equations yields 40MB30MT=120    4MB3MT=1240 M_B - 30 M_T = 120 \implies 4 M_B - 3 M_T = 12.
Since MTM_T could be 1616 (making MB=15M_B = 15, so MT>MBM_T > M_B is Yes) or MTM_T could be 88 (making MB=9M_B = 9, so MT>MBM_T > M_B is No), Statement (1) alone is NOT sufficient.
3
Evaluate Statement (2) independently.
Statement (2) gives Mboth=15M_{both} = 15. Without knowing the total asset values or subgroup means, we cannot compare MTM_T and MBM_B.
Statement (2) alone is NOT sufficient.
4
Evaluate Statements (1) and (2) together.
Substituting Mboth=15M_{both} = 15 into Statement (1) equations: 30MT+20(15)=600    30MT=300    MT=1030 M_T + 20(15) = 600 \implies 30 M_T = 300 \implies M_T = 10. Similarly, 40MB+20(15)=720    40MB=420    MB=10.540 M_B + 20(15) = 720 \implies 40 M_B = 420 \implies M_B = 10.5. Since 10>10.510 > 10.5 is definitively FALSE, we get a clear 'No' response.
In Yes/No Data Sufficiency questions, a definitive 'No' means the combined statements are sufficient.

Key Concept

Data Sufficiency decision logic for overlapping sets combined with weighted averages
Estimated Time:2m 0s
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